(x+3)^2=x^2+6

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Solution for (x+3)^2=x^2+6 equation: 



(x+3)^2=x^2+6

We move all terms to the left:

(x+3)^2-(x^2+6)=0

We get rid of parentheses

-x^2+(x+3)^2-6=0

We add all the numbers together, and all the variables

-1x^2+(x+3)^2-6=0

We move all terms containing x to the left, all other terms to the right

-1x^2+(x+3)^2=6

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